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5 changes: 5 additions & 0 deletions app/calculator.py
Original file line number Diff line number Diff line change
Expand Up @@ -14,3 +14,8 @@ def divide(x, y):
if y == 0:
return 'Cannot divide by 0'
return x * 1.0 / y

def divide2(x, y):
if y == 0:
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The new divide2 method appears to be a duplicate of the existing divide method. Having duplicate code increases maintenance burden and potential for bugs. If there's a specific reason for having a second division method, it should be clearly documented. Otherwise, this addition should be removed.

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Both division methods mix return types (string for error case, float for success). This is not a recommended practice in Python. Consider using exception handling instead of returning error strings. This makes the function's contract clearer and allows for proper error handling by callers.

return 'Cannot divide by 0'
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Consider using a more robust error handling approach. Returning a string for error cases while returning numbers for successful cases creates inconsistent return types, which can lead to type-related bugs. Consider raising a ZeroDivisionError exception instead, which is more pythonic and allows callers to handle the error appropriately.

Suggested change
if y == 0:
return 'Cannot divide by 0'
if y == 0:
raise ZeroDivisionError("Cannot divide by zero")

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Returning a string for error conditions is inconsistent with typical Python practices and creates type safety issues. Consider raising a ZeroDivisionError exception instead, which is more pythonic and allows calling code to handle the error appropriately.

Suggested change
if y == 0:
return 'Cannot divide by 0'
if y == 0:
raise ZeroDivisionError("Cannot divide by zero")

return x * 1.0 / y
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This method is an exact duplicate of the existing divide method (lines 14-16). Code duplication should be avoided as it increases maintenance burden and the risk of inconsistencies. Consider either: 1) Removing this duplicate method if it's not needed, 2) Giving it a meaningful name that reflects its specific purpose if it serves a different use case, or 3) Refactoring both methods to use a common implementation if they're meant to have the same behavior.

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This function appears to be an exact duplicate of the existing divide method. Code duplication should be avoided as it increases maintenance burden and the risk of bugs. If this is intended as a refactor, consider removing the original divide method instead of adding a duplicate. If this serves a different purpose, please provide a more descriptive name and documentation explaining the difference.

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This function is an exact duplicate of the existing divide function. Code duplication should be avoided as it increases maintenance burden and potential for bugs. If you need a second division function with different behavior, please implement the specific differences. If this was added by mistake, consider removing it.

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The function indentation appears incorrect. Based on the diff context, this function should be at the module level (same indentation as other functions), not nested inside another function.

Suggested change
def divide2(x, y):
if y == 0:
return 'Cannot divide by 0'
return x * 1.0 / y
def divide2(x, y):
if y == 0:
return 'Cannot divide by 0'
return x * 1.0 / y

Comment on lines +18 to +21
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This method is an exact duplicate of the existing divide method. Code duplication violates the DRY (Don't Repeat Yourself) principle and creates unnecessary maintenance burden. If you need a different division implementation, consider:

  1. Modifying the existing divide method if the behavior needs to change
  2. Creating a method with a more descriptive name that explains why it differs from divide
  3. If this is truly needed, document why both methods exist

If this was added accidentally, please remove it.

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The indentation appears to be incorrect. Based on the existing code structure, this method should be indented to align with other class methods. The current indentation suggests this might not be properly part of the Calculator class.

Suggested change
def divide2(x, y):
if y == 0:
return 'Cannot divide by 0'
return x * 1.0 / y
def divide2(x, y):
if y == 0:
return 'Cannot divide by 0'
return x * 1.0 / y