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Fix Elixir Lexer Sigil Handling #2190

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Fix Elixir Lexer Sigil Handling #2190

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7abe6e6
Fix Elixir sigil interpolation
P-SiZK Jan 4, 2026
163bcba
Fix Elixir lexer sigil pattern to match specification
P-SiZK Jan 4, 2026
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12 changes: 6 additions & 6 deletions lib/rouge/lexers/elixir.rb
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Original file line number Diff line number Diff line change
Expand Up @@ -99,27 +99,27 @@ def self.detect?(text)

state :sigil_strings do
# ~-sigiled strings
# ~(abc), ~[abc], ~<abc>, ~|abc|, ~r/abc/, etc
# ~r(abc), ~r[abc], ~r<abc>, ~r|abc|, ~r/abc/, etc
# Cribbed and adjusted from Ruby lexer
delimiter_map = { '{' => '}', '[' => ']', '(' => ')', '<' => '>' }
# Match a-z for custom sigils too
sigil_opens = Regexp.union(delimiter_map.keys + %w(| / ' "))
rule %r/~([A-Za-z])?(#{sigil_opens})/ do |m|
# Match [a-z] or [A-Z][A-Z0-9]* for custom sigils too
rule %r/~([a-z]|[A-Z][A-Z0-9]*)(#{sigil_opens})/ do |m|
open = Regexp.escape(m[2])
close = Regexp.escape(delimiter_map[m[2]] || m[2])
interp = /[SRCW]/ === m[1]
interp = /^[srcw]$/ === m[1]
toktype = Str::Other

puts " open: #{open.inspect}" if @debug
puts " close: #{close.inspect}" if @debug

# regexes
if 'Rr'.include? m[1]
if m[1] == 'r' || m[1] == 'R'
toktype = Str::Regex
push :regex_flags
end

if 'Ww'.include? m[1]
if m[1] == 'w' || m[1] == 'W'
push :list_flags
end

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19 changes: 12 additions & 7 deletions spec/visual/samples/elixir
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Expand Up @@ -63,13 +63,18 @@ string |> String.split(~r/[ -]/) |> Enum.map(&abbreviate_word/1) |> Enum.join()
~c||
~c//

~S(inter #{pol <> "ati#{o}"} n)
~S[inter #{pol <> "ati#{o}"} n]
~S<inter #{pol <> "ati#{o}"} n>
~S'inter #{pol <> "ati#{o}"} n'
~S"inter #{pol <> "ati#{o}"} n"
~S|inter #{pol <> "ati#{o}"} n|
~S/inter #{pol <> "ati#{o}"} n/
~s(inter #{pol <> "ati#{o}"} n)
~s[inter #{pol <> "ati#{o}"} n]
~s<inter #{pol <> "ati#{o}"} n>
~s'inter #{pol <> "ati#{o}"} n'
~s"inter #{pol <> "ati#{o}"} n"
~s|inter #{pol <> "ati#{o}"} n|
~s/inter #{pol <> "ati#{o}"} n/

# custom sigils
~i(13)
~CUSTOM(custom uppercase)
~ABC123(with digits)

# first is Operator, second is &1 variable
&(&1)
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