Remove hanging parenthesis from example signature.

src/ty.md

@@ -62,8 +62,8 @@ Here is a summary:
 | Describe the *syntax* of a type: what the user wrote (with some desugaring).  | Describe the *semantics* of a type: the meaning of what the user wrote. |
 | Each `rustc_hir::Ty` has its own spans corresponding to the appropriate place in the program. | Doesn’t correspond to a single place in the user’s program. |
 | `rustc_hir::Ty` has generics and lifetimes; however, some of those lifetimes are special markers like [`LifetimeKind::Implicit`][implicit]. | `ty::Ty` has the full type, including generics and lifetimes, even if the user left them out |
-| `fn foo(x: u32) → u32 { }` - Two `rustc_hir::Ty` representing each usage of `u32`, each has its own `Span`s, and `rustc_hir::Ty` doesn’t tell us that both are the same type | `fn foo(x: u32) → u32 { }` - One `ty::Ty` for all instances of `u32` throughout the program, and `ty::Ty` tells us that both usages of `u32` mean the same type. |
-| `fn foo(x: &u32) -> &u32)` - Two `rustc_hir::Ty` again. Lifetimes for the references show up in the `rustc_hir::Ty`s using a special marker, [`LifetimeKind::Implicit`][implicit]. | `fn foo(x: &u32) -> &u32)`- A single `ty::Ty`. The `ty::Ty` has the hidden lifetime param. |
+| `fn foo(x: u32) -> u32 { }` - Two `rustc_hir::Ty` representing each usage of `u32`, each has its own `Span`s, and `rustc_hir::Ty` doesn’t tell us that both are the same type | `fn foo(x: u32) -> u32 { }` - One `ty::Ty` for all instances of `u32` throughout the program, and `ty::Ty` tells us that both usages of `u32` mean the same type. |
+| `fn foo(x: &u32) -> &u32 { }` - Two `rustc_hir::Ty` again. Lifetimes for the references show up in the `rustc_hir::Ty`s using a special marker, [`LifetimeKind::Implicit`][implicit]. | `fn foo(x: &u32) -> &u32 { }`- A single `ty::Ty`. The `ty::Ty` has the hidden lifetime param. |
 
 [implicit]: https://doc.rust-lang.org/nightly/nightly-rustc/rustc_hir/hir/enum.LifetimeKind.html#variant.Implicit