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solution m2-015 #175

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43fd57b
solution m2-015
Stefano-A Aug 2, 2024
08ac09f
solution m2-015 fix
Stefano-A Aug 6, 2024
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46 changes: 46 additions & 0 deletions projects/015-parity-bits/python/main.py
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Original file line number Diff line number Diff line change
@@ -0,0 +1,46 @@
# byte =[]
# x = 0
# u_bit = 'none'

# while u_bit != '':
# x = x + 1
# u_bit = input(f'Insert the bit number {x}: ')
# byte.append(u_bit)


# if x == 9 and u_bit == '':
# n = byte.count('1')
# if n % 2 == 0:
# print('The parity bit is: 0')

# else:
# print('The parity bit is: 1')

# else:
# print('The number of bits must be equal to 8')





byte = []
x = 0
u_bit = 'none'

while x < 8 and u_bit != '':
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could you find a way to optimize the while loop?

x = x + 1
u_bit = input(f'Insert the bit number {x}: ')
byte.append(u_bit)


if x <= 8 and u_bit == '':
print('The number of bits must be equal to 8')

else:
n = byte.count('1')
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is possible to avoid this count?


if n % 2 == 0:
print('The parity bit is: 0')

else:
print('The parity bit is: 1')