Remove a redundant constraint in BigAddModP #24
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Since 0<= a,b < p, 0<= add.out < 2p. (1) If 0 <= add.out < p, lt.out = 1 and sub.out = add.out, which means that 0 <= sub.out < p. (2) If p <= add.out < 2p, lt.out = 0 and sub.out = add.out - p, which also means that 0 <= sub.out < p. And because p is a bigint of length k, sub.out[k] must be 0.
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Since 0<= a,b < p, 0<= add.out < 2p. (1) If 0 <= add.out < p, lt.out = 1 and sub.out = add.out, which means that 0 <= sub.out < p. (2) If p <= add.out < 2p, lt.out = 0 and sub.out = add.out - p, which also means that 0 <= sub.out < p. And because p is a bigint of length k, sub.out[k] must be 0.