Updates and small fixes, move ascii_tree to helpers

docs/howto/supplier_tree.md

@@ -112,7 +112,7 @@ print(mapping2mermaid(rows, title=title))
 The table below shows the values for the decision model.
 Each row of the table corresponds to a path through the decision model diagram above.
 
-% include-markdown "../_includes/_scrollable_table.md" heading-offset=1 %}
+{% include-markdown "../_includes/_scrollable_table.md" heading-offset=1 %}
 
 ```python exec="true" idprefix=""
 

src/README.md

@@ -27,7 +27,7 @@ After installation, import the package and explore the examples:
     print(to_play.LATEST.model_dump_json(indent=2))
 
     #Show decision tree in ascii text art
-    from ssvc.decision_tables.base import ascii_tree
+    from ssvc.decision_tables.helpers import ascii_tree
     print(ascii_tree(to_play.LATEST))
 
 Explanation
@@ -92,7 +92,7 @@ For usage in vulnerability management scenarios consider the following popular S
     print(CISACoordinate.model_dump_json(indent=2))
 
     #Print CISA Decision Table as an ascii tree
-    from ssvc.decision_tables.base import ascii_tree
+    from ssvc.decision_tables.helpers import ascii_tree
     print(ascii_tree(CISACoordinate))
 
 

src/ssvc/decision_tables/base.py

@@ -702,88 +702,7 @@ def check_topological_order(dt: DecisionTable) -> list[dict]:
         df, target=target, target_value_order=target_value_order
     )
 
-def build_tree(df: pd.DataFrame, columns: pd.Index | list[str]) -> dict[str, dict[str, str] | list[str]] | list[str]:
-    """
-    Recursively build a nested dict:
-    {feature_value: subtree_or_list_of_outcomes}
-
-    This tree should preserve the original row order of the DataFrame.
-    """
-    # Base case: if only one column is left, it's the outcome.
-    if len(columns) == 1:
-        # Last column: return a list of outcomes.
-        return df[columns[0]].astype(str).tolist()
-
-    # Get the first feature column and the rest of the columns.
-    first, rest = columns[0], columns[1:]
-    tree = {}
-
-    # Iterate through the unique values of the first column in the order they appear.
-    # This is the key change to preserve the original CSV order.
-    for val in df[first].unique():
-        # Filter the DataFrame to get the group for the current value.
-        group = df[df[first] == val]
-        # Recursively build the subtree for this group.
-        tree[str(val)] = build_tree(group, rest)
-
-    return tree
-
-def draw_tree(node: dict | list, prefix: str="", lines: list | None = None) -> list:
-    """
-    Pretty-print nested dict/list as a tree.
-    """
-    if lines is None:
-        lines = []
-
-    if isinstance(node, dict):
-        items = list(node.items())
-        for i, (k, v) in enumerate(items):
-            # Determine the branch characters for the tree.
-            branch = "└── " if i == len(items) - 1 else "├── "
-            lines.append(prefix + branch + k + " " * 4)
-
-            # Calculate the prefix for the next level of the tree.
-            next_prefix = prefix + (" " * 16 if i == len(items) - 1 else "│" + " " * 15)
-            # Recursively draw the subtree.
-            draw_tree(v, next_prefix, lines)
-    else:  # list of outcomes
-        for i, leaf in enumerate(node):
-            # Determine the branch characters for the leaves.
-            branch = "└── " if i == len(node) - 1 else "├── "
-            lines.append(prefix + branch + f"[{leaf}]")
-
-    return lines
-
 def ascii_tree(dt: DecisionTable, df: pd.DataFrame | None = None) -> str:
-    """
-    Reads a Pandas data frame, builds a decision tree, and returns its ASCII representation.
-    """
-    # Check for the optional 'row' column and drop it if it exists.
-    if df == None:
-        df = decision_table_to_longform_df(dt)
-
-    if 'row' in df.columns:
-        df.drop(columns='row', inplace=True)
-
-    # Separate feature columns from the outcome column.
-    feature_cols = list(df.columns[:-1])
-    outcome_col  = df.columns[-1]
-
-    # Build the tree structure.
-    tree = build_tree(df, feature_cols + [outcome_col])
-    # Draw the tree into a list of strings.
-    lines = draw_tree(tree)
-
-    # Generate the header line.
-    header = ""
-    for item in df.columns:
-        if len(item) > 14:
-            header = header + item[0:12] + ".." + " | "
-        else:
-            header = header + item + " " * (14 - len(item)) + " | "
-
-    # Generate the separator line.
-    sep = "-" * len(header)
-
-    # Combine the header, separator, and tree lines into a single string.
-    return "\n".join([header, sep] + lines)
+    """ Function moved to helpers.py see there for details """
+    from . import helpers
+    return helpers.ascii_tree(dt, df)

src/ssvc/decision_tables/helpers.py

@@ -24,6 +24,7 @@
 
 
 import logging
+import pandas as pd
 
 from ssvc.decision_tables.base import (
     DecisionTable,
@@ -215,7 +216,7 @@ def mapping2mermaid(rows: list[dict[str:str]], title: str = None) -> str:
 
 
 def dt2df_md(
-    dt: "DecisionTable",
+    dt: DecisionTable,
     longform: bool = True,
 ) -> str:
     """
@@ -224,7 +225,7 @@ def dt2df_md(
         decision_table (DecisionTable): The decision table to convert.
         longform (bool): Whether to return the longform or shortform DataFrame.
     Returns:
-        str: A string representation of the DataFrame in CSV format.
+        str: A string representation of the DataFrame in text/markdown format.
     """
     if longform:
         df = decision_table_to_longform_df(dt)
@@ -234,6 +235,161 @@ def dt2df_md(
     df.index.rename("Row", inplace=True)
     return df.to_markdown(index=True)
 
+def dt2df_html(
+        dt: DecisionTable,
+        longform: bool = True) -> str:
+    """
+    Converts a Decision Tree and represent it in friendly HTML Code
+    Args:
+        decision_table (DecisionTable): The decision table to convert.
+        longform (bool): Whether to return the longform or shortform DataFram, defaults to true    
+    Returns:
+        str: A string representation of the DataFrame in HTML format.  
+    """
+
+    if longform:
+        df = decision_table_to_longform_df(dt)
+    else:
+        df = decision_table_to_shortform_df(dt)
+
+    df = decision_table_to_longform_df(dt)
+    ncols = len(df.columns)
+    nrows = len(df)
+
+    # Precompute rowspan info for every cell
+    # rowspan[i][j] = number of rows this cell should span; 0 means skip (because merged above)
+    rowspan = [[1]*ncols for _ in range(nrows)]
+
+    for col in range(ncols):
+        r = 0
+        while r < nrows:
+            start = r
+            val = df.iat[r, col] #data_rows[r][col]
+            # Count how many subsequent rows have same value
+            while r + 1 < nrows and df.iat[r + 1, col] == val:#data_rows[r + 1][col] == val:
+                r += 1
+            span = r - start + 1
+            if span > 1:
+                # Assign span to first, mark rest as 0 (skip)
+                rowspan[start][col] = span
+                for k in range(start + 1, start + span):
+                    rowspan[k][col] = 0
+            r += 1
+
+    # Build HTML
+    html = ["""<style>
+    table,th,td,tr { border-spacing: 0px; border: 1px solid cyan; padding: 0px; font-family: verdana,courier }
+    .decision_table th { font-weight: bold; }
+    td.decision_point { vertical-align: middle}
+    td.outcome { font-style: italic; font-weight: bold}
+</style>"""]
+    html.append("<table class=\"decision_table\">")
+    html.append("  <tr>" + "".join(f"<th>{h}</th>" for h in df.columns) + "</tr>")
+
+    for i, row in df.iterrows(): #for i, row in enumerate(df):
+        cells = []
+        j = 0
+        for _, val in row.items(): #enumerate(row):
+            tdtype = "decision_point"
+            if j == len(row) - 1:
+                tdtype = "outcome"
+            if rowspan[i][j] > 0:
+                span = rowspan[i][j]
+                if span > 1:
+                    cells.append(f'<td rowspan="{span}" class="{tdtype}">{val}</td>')
+                else:
+                    cells.append(f'<td class="{tdtype}">{val}</td>')
+            j = j + 1
+        html.append("  <tr>" + "".join(cells) + "</tr>")
+
+    html.append("</table>")
+    return "".join(html)
+
+def build_tree(df: pd.DataFrame, columns: pd.Index | list[str]) -> dict[str, dict[str, str] | list[str]] | list[str]:
+    """
+    Helper function recursively build a nested dict:
+    {feature_value: subtree_or_list_of_outcomes}
+    This tree should preserve the original row order of the DataFrame.
+    """
+    # Base case: if only one column is left, it's the outcome.
+    if len(columns) == 1:
+        # Last column: return a list of outcomes.
+        return df[columns[0]].astype(str).tolist()
+
+    # Get the first feature column and the rest of the columns.
+    first, rest = columns[0], columns[1:]
+    tree = {}
+
+    # Iterate through the unique values of the first column in the order they appear.
+    # This is the key change to preserve the original CSV order.
+    for val in df[first].unique():
+        # Filter the DataFrame to get the group for the current value.
+        group = df[df[first] == val]
+        # Recursively build the subtree for this group.
+        tree[str(val)] = build_tree(group, rest)
+
+    return tree
+
+def draw_tree(node: dict | list, prefix: str="", lines: list | None = None) -> list:
+    """
+    Pretty-print nested dict/list as a tree.
+    """
+    if lines is None:
+        lines = []
+
+    if isinstance(node, dict):
+        items = list(node.items())
+        for i, (k, v) in enumerate(items):
+            # Determine the branch characters for the tree.
+            branch = "└── " if i == len(items) - 1 else "├── "
+            lines.append(prefix + branch + k + " " * 4)
+
+            # Calculate the prefix for the next level of the tree.
+            next_prefix = prefix + (" " * 16 if i == len(items) - 1 else "│" + " " * 15)
+            # Recursively draw the subtree.
+            draw_tree(v, next_prefix, lines)
+    else:  # list of outcomes
+        for i, leaf in enumerate(node):
+            # Determine the branch characters for the leaves.
+            branch = "└── " if i == len(node) - 1 else "├── "
+            lines.append(prefix + branch + f"[{leaf}]")
+
+    return lines
+
+def ascii_tree(dt: DecisionTable, df: pd.DataFrame | None = None) -> str:
+    """
+    Reads a Pandas data frame, builds a decision tree, and returns its ASCII representation.
+    """
+    # Check for the optional 'row' column and drop it if it exists.
+    if df == None:
+        df = decision_table_to_longform_df(dt)
+
+    if 'row' in df.columns:
+        df.drop(columns='row', inplace=True)
+
+    # Separate feature columns from the outcome column.
+    feature_cols = list(df.columns[:-1])
+    outcome_col  = df.columns[-1]
+
+    # Build the tree structure.
+    tree = build_tree(df, feature_cols + [outcome_col])
+    # Draw the tree into a list of strings.
+    lines = draw_tree(tree)
+
+    # Generate the header line.
+    header = ""
+    for item in df.columns:
+        if len(item) > 14:
+            header = header + item[0:12] + ".." + " | "
+        else:
+            header = header + item + " " * (14 - len(item)) + " | "
+
+    # Generate the separator line.
+    sep = "-" * len(header)
+
+    # Combine the header, separator, and tree lines into a single string.
+    return "\n".join([header, sep] + lines)
+
 
 def main():
     pass